JEE (M) results out in 7 days, 15 candidates score 100 percentile
Manash.Gohain@timesgroup.com
New Delhi:20.01.2019
The results for Joint Entrance Examination – Main 1 (JEE-main 1) were declared in a record time of seven days on Saturday.
The computer-based test was held on January 12 and the scheduled date for results as announced by the National Testing Agency (NTA) earlier was January 31. The examination was completely glitch free and despite the inclement weather and the board exams scheduled in February, 94.1% of the 9.29 lakh registered aspirants appeared for the tests.
Fifteen candidates are in the 100 percentile category (100 NTA score). In fact, a total of 8,816 candidates were in the 99-100 percentile category.
The percentile system was introduced in JEE because the test was spread over five days and 10 sessions.
The results of paper-II (for architecture courses) will be announced later.
This is the first time the exams have been completely conducted on computers and it will also be the first time that aspirants unhappy with their scores have a second shot at improving them in April, 2019.
While declaring the results, NTA announced the individual percentile of the candidate and has not ranked the students. According to NTA, “The ranks of the candidates will be released taking into consideration better of the two NTA scores of all candidates appearing in January 2019 and April 2019 examinations. The final merit list will be declared only after the conduct of the JEE – main 2 in April, 2019”.
Students appeared for the computer-based test on January 12
Next online application for JEE Main 2 from Feb 8
Among the candidates who secured 100 NTA score, four are from Telangana, three from Maharashtra, two from Uttar Pradesh and Rajasthan, and one each from Punjab, Karnataka, Andhra Pradesh and Madhya Pradesh.
NTA scores are normalized scores across multi session papers and are based on the relative performance of all those who appeared for the examination in one session.
The marks obtained are converted into a scale ranging from 100 to 0 for each session of examinees.
According to NTA officials, the merit list or the ranks will be calculated based on the performances of candidates from both the January and April exam.
“The topper(s) will be the one who scored 100 percentile overall. In case of a tie, the 100 percentile of the individual subjects in the order of physics, chemistry and mathematics will determine the ranks followed by the least negative marking received.
“In case of tie even after this, the older candidate will be given priority in the ranking,” said a senior NTA official.
The next online application process for JEE – Main 2 shall start from February 8, 2019 and shall remain open till March 7, 2019.
The uploading of images and payment of the application fee will be upto March 8, 2019. The examination will be conducted in computer-based-test mode between April 6 and 20, 2019.
Manash.Gohain@timesgroup.com
New Delhi:20.01.2019
The results for Joint Entrance Examination – Main 1 (JEE-main 1) were declared in a record time of seven days on Saturday.
The computer-based test was held on January 12 and the scheduled date for results as announced by the National Testing Agency (NTA) earlier was January 31. The examination was completely glitch free and despite the inclement weather and the board exams scheduled in February, 94.1% of the 9.29 lakh registered aspirants appeared for the tests.
Fifteen candidates are in the 100 percentile category (100 NTA score). In fact, a total of 8,816 candidates were in the 99-100 percentile category.
The percentile system was introduced in JEE because the test was spread over five days and 10 sessions.
The results of paper-II (for architecture courses) will be announced later.
This is the first time the exams have been completely conducted on computers and it will also be the first time that aspirants unhappy with their scores have a second shot at improving them in April, 2019.
While declaring the results, NTA announced the individual percentile of the candidate and has not ranked the students. According to NTA, “The ranks of the candidates will be released taking into consideration better of the two NTA scores of all candidates appearing in January 2019 and April 2019 examinations. The final merit list will be declared only after the conduct of the JEE – main 2 in April, 2019”.
Students appeared for the computer-based test on January 12
Next online application for JEE Main 2 from Feb 8
Among the candidates who secured 100 NTA score, four are from Telangana, three from Maharashtra, two from Uttar Pradesh and Rajasthan, and one each from Punjab, Karnataka, Andhra Pradesh and Madhya Pradesh.
NTA scores are normalized scores across multi session papers and are based on the relative performance of all those who appeared for the examination in one session.
The marks obtained are converted into a scale ranging from 100 to 0 for each session of examinees.
According to NTA officials, the merit list or the ranks will be calculated based on the performances of candidates from both the January and April exam.
“The topper(s) will be the one who scored 100 percentile overall. In case of a tie, the 100 percentile of the individual subjects in the order of physics, chemistry and mathematics will determine the ranks followed by the least negative marking received.
“In case of tie even after this, the older candidate will be given priority in the ranking,” said a senior NTA official.
The next online application process for JEE – Main 2 shall start from February 8, 2019 and shall remain open till March 7, 2019.
The uploading of images and payment of the application fee will be upto March 8, 2019. The examination will be conducted in computer-based-test mode between April 6 and 20, 2019.
No comments:
Post a Comment